Using the exact lattice identification
O_sing = { (x_7,x_1,x_5) in Z_3^3 : x_1 ≡ x_5 mod 3 },
choose the basis
e7 = (1,0,0),
epair = (0,1,1),
n = (0,3,0).
Then multiplication is coordinatewise in Z_3^3, so the basis satisfies
e7^2 = e7,
epair^2 = epair,
e7*epair = 0,
e7*n = 0,
epair*n = n,
n^2 = 3n.
Hence
O_sing ≅ Z_3 e7 ⊕ Z_3 epair ⊕ Z_3 n
≅ Z_3 × Z_3[eta]/(eta^2 - 3 eta),
with eta = n on the pair factor.
Reducing modulo 3 gives
O_sing / 3 O_sing ≅ F_3 × F_3[eps]/(eps^2),
since n^2 = 3n collapses to eps^2 = 0.
In the basis [e7, epair, n], left multiplication by the basis elements is
L(e7) = [[1, 0, 0], [0, 0, 0], [0, 0, 0]]
L(epair) = [[0, 0, 0], [0, 1, 0], [0, 0, 1]]
L(n) = [[0, 0, 0], [0, 0, 0], [0, 1, 3]]
Modulo 3, the pair block becomes a Jordan block:
epair ↦ identity on the pair block,
n ↦ nilpotent with n^2 = 0.
| operator | residue coords in [e7, epair, n] |
matrix mod 3 |
|---|---|---|
T_1 |
[1, 1, 0] |
[[1, 0, 0], [0, 1, 0], [0, 0, 1]] |
T_3 |
[1, 0, 0] |
[[1, 0, 0], [0, 0, 0], [0, 0, 0]] |
T_7 |
[2, 2, 2] |
[[2, 0, 0], [0, 2, 0], [0, 2, 2]] |
T_11 |
[0, 0, 2] |
[[0, 0, 0], [0, 0, 0], [0, 2, 0]] |
T_19 |
[2, 0, 0] |
[[2, 0, 0], [0, 0, 0], [0, 0, 0]] |
T_43 |
[2, 1, 1] |
[[2, 0, 0], [0, 1, 0], [0, 1, 1]] |
T_67 |
[2, 1, 1] |
[[2, 0, 0], [0, 1, 0], [0, 1, 1]] |
T_163 |
[1, 2, 0] |
[[1, 0, 0], [0, 2, 0], [0, 0, 2]] |
If one writes
I = e7 + epair, E = e7, N = -n,
then the residue formulas become exactly
T_3 = E,
T_19 = -E,
T_11 = N,
T_7 = -I + N,
T_43 = T_67 = I + E - N,
T_163 = -I - E.
So the singular Hecke node is exactly one split idempotent branch e7 together with one rank-2 pair factor whose deformation parameter n satisfies n^2 = 3n.