Exact Residue-Module Structure of the Singular Hecke Node

Reducing the exact local presentation modulo 3 gives

A = O_sing / 3 O_sing ≅ F_3 × F_3[eps]/(eps^2).

In the residue basis

[ e7bar , epairbar , nbar ],

the regular module splits exactly as

A_reg ≅ chi_v7 ⊕ P_pair,

where:

So the residue node is not a single length-3 indecomposable. Its only non-semisimplicity is internal to the glued pair block.

Pair block

On the basis [epairbar, nbar], the pair block matrices are

E = [[0,0],[0,0]],
N = [[0,0],[2,0]],
I = [[1,0],[0,1]].

So N kills the top and maps the top line onto the socle; this is exactly the dual-number Jordan block.

Ext

The Ext table is

Ext^1(chi_pair, chi_pair) ≅ F_3,
Ext^1(chi_v7, chi_pair) = 0,
Ext^1(chi_pair, chi_v7) = 0,
Ext^1(chi_v7, chi_v7)   = 0.

So the split V7 branch is completely disconnected from the extension theory. All residue-level deformation lives inside the V1/V5 pair.