The exact local pair factor is
R = Z_3[eta]/(eta^2 - 3 eta).
Equivalently,
R ≅ Z_3 ×_{F_3} Z_3
= {(a,b) in Z_3 × Z_3 : a ≡ b mod 3}.
So the singular Hecke object is literally the split nodal curve over Z_3: two smooth Z_3-branches glued along the common residue point modulo 3.
12R is a hypersurfaceS = Z_3 × Z_3f = 3S = mR ⊂ SSo there is only one genuine singularity here: a split A_1-type node.
Let m = (3,eta). In the associated graded ring, write
a = [3] in m/m^2,
g = [eta] in m/m^2.
Since eta^2 = 3 eta, one gets
gr_m(R) ≅ F_3[a,g]/(g^2 - a g) = F_3[a,g]/(g(g-a)).
So the tangent cone is already the union of two crossing lines. The node is visible in first-order infinitesimal geometry.
Because R/m has dimension 1 and each m^r/m^(r+1) has dimension 2 for r >= 1, the Hilbert series is
H_R(t) = 1 + 2t + 2t^2 + ... = (1+t)/(1-t).
For the full singular order
O_sing ≅ Z_3 × R,
the residue semisimple piece has dimension 2 and every deeper Jacobson layer has width 3, so
H_{O_sing}(t) = 2 + 3t + 3t^2 + ... = (2+t)/(1-t).
For the pair factor, ideals of index 3^n occur with multiplicities
c_0 = 1,
c_{2r-1} = 1,
c_{2r} = 4 (r >= 1).
Hence the local ideal zeta function is
zeta_R(s) = 1 + sum_{r>=1} x^(2r-1) + 4 sum_{r>=1} x^(2r)
= (1 + x + 3x^2)/(1 - x^2),
with x = 3^{-s}.
For the full singular order O_sing ≅ Z_3 × R, one more smooth branch contributes the factor (1-x)^{-1}:
zeta_{O_sing}(s) = (1 + x + 3x^2)/((1-x)(1-x^2)).
This is the cleanest current answer to the shape of the object: a smooth branch plus a split node, with completely explicit infinitesimal and ideal-theoretic geometry.